SOLUTION: Solve the following algebraically: {{{9^(x+1)=27^(3x)}}} my work: {{{(3^2)^(x+1)=(3^3)^(3x)}}} 2x+2=9x then subtract 2x from both sides 2=7x then divide out 7 to get x alo

Algebra ->  Inverses -> SOLUTION: Solve the following algebraically: {{{9^(x+1)=27^(3x)}}} my work: {{{(3^2)^(x+1)=(3^3)^(3x)}}} 2x+2=9x then subtract 2x from both sides 2=7x then divide out 7 to get x alo      Log On


   

Question 697147: Solve the following algebraically:
9%5E%28x%2B1%29=27%5E%283x%29
my work:
%283%5E2%29%5E%28x%2B1%29=%283%5E3%29%5E%283x%29
2x+2=9x then subtract 2x from both sides
2=7x then divide out 7 to get x alone
x=2/7
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following algebraically:
9%5E%28x%2B1%29=27%5E%283x%29
my work:
%283%5E2%29%5E%28x%2B1%29=%283%5E3%29%5E%283x%29
2x+2=9x then subtract 2x from both sides
2=7x then divide out 7 to get x alone
x=2/7
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Looks good.