SOLUTION: Find the real root of the transcedental equation cos x - 3x + 1 = 0 correct to four decimal places using iteration method.

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Question 696991: Find the real root of the transcedental equation cos x - 3x + 1 = 0 correct to four decimal places using iteration method.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
NOTE: In math, when we see cos%28x%29, we assume x is measured in radians, not degrees.

cos+x+-+3x+%2B+1+=+0 <--> cos+x+%2B+1+=+3x
We know that the graphs of y=cos%28x%29%2B1 and y=3x look like this:
graph%28300%2C150%2C-2%2C7%2C-2%2C2.5%2Ccos%28x%29%2B1%2C3x%29
We need to look for the point where they intersect.

At x=0.5, y=cos%28x%29%2B1 is greater than y=3x ,
cos%280.5%29%2B1=about1.8776%3E1.5=3%2A0.5 ,
but at x=0.7, y=cos%28x%29%2B1 is lesser than y=3x ,
cos%280.7%29%2B1=about1.7648%3C2.1=3%2A0.7 ,
so the answer is between x=0.5 and x=0.7 .
For x=0.6, y=cos%28x%29%2B1 is greater than y=3x , with
cos%280.6%29%2B1=about1.8253%3E1.8=3%2A0.6 ,
but they are very close, much closer that at x=0.7 ,
so the answer is between x=0.6 and x=0.7 ,
but we expect it to be close to x=0.6 .
For x=0.61, y=cos%28x%29%2B1 is lesser than y=3x , with
cos%280.61%29%2B1=about1.8196%3C1.83=3%2A0.61 ,
so the answer is between x=0.6 and x=0.61 .
We may try x=0.605%7D%7D%2C+getting%0D%0A%7B%7B%7Bcos%280.605%29%2B1=about1.8225%3E1.815=3%2A0.605 ,
where y=cos%28x%29%2B1 is still a bit too high,
and then try x=0.607, getting
cos%280.607%29%2B1=about1.8214%3E1.8210=3%2A0.607 ,
where y=cos%28x%29%2B1 is still a bit too high,
but very, very close.
We could next try x=0.6071, getting
cos%280.6071%29%2B1=about1.82131%3E1.8213=3%2A0.6071 ,
where y=cos%28x%29%2B1 is still a hair too high.
We can then try x=0.6072, getting
cos%280.6072%29%2B1=about1.8212%3E1.8216=3%2A0.6072 ,
where y=cos%28x%29%2B1 is a bit too low.
That tells us that the answer is between x=0.6071 and x=0.6072 .
We seemed to be closer at x=0.6071, so maybe we should try x=0.60714 .
For x=0.60714, y=cos%28x%29%2B1 is also a bit too low, with
cos%280.60714%29%2B1=about and x=0.60714 ,
both of which round to highlight%280.6071%29 .