SOLUTION: Solve log(base6) (x^2+7)=log(base6)(1-5x)

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Question 696959: Solve log(base6) (x^2+7)=log(base6)(1-5x)
Found 2 solutions by lwsshak3, MathLover1:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve log(base6) (x^2+7)=log(base6)(1-5x)
x^2+7=1-5x
x^2+5x+6=0
(x+3)(x+2)=0
x+3=0
x=-3
or
x+2=0
x=-2

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
log%286%2C%28x%5E2%2B7%29%29=log%286%2C%281-5x%29%29...this will be equal for

x%5E2%2B7=1-5x...now find solutions for x

x%5E2%2B5x%2B7-1=0

x%5E2%2B5x%2B6=0.....use quadratic formula

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+...enter a=1, b=5, and c=6+

x+=+%28-5+%2B-+sqrt%28+5%5E2-4%2A1%2A6+%29%29%2F%282%2A1%29+

x+=+%28-5+%2B-+sqrt%28+25-24+%29%29%2F2+

x+=+%28-5+%2B-+sqrt%28+1+%29%29%2F2+

x+=+%28-5+%2B-+1%29%2F2+

solutions:
x+=+%28-5+%2B+1%29%2F2+
x+=+-4%2F2+
highlight%28x+=+-2%29+
or
x+=+%28-5+-+1%29%2F2+
x+=+-6%2F2+
highlight%28x+=+-3%29+