SOLUTION: (n+3)(2n+3)=(n+2)^2+(n-2)^2

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Question 696952: (n+3)(2n+3)=(n+2)^2+(n-2)^2
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(n+3)(2n+3)=(n+2)^2+(n-2)^2
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3n^2+ 9n + 9 = n^2+4n+4 + n^2-4n+4
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3n^2 +9n +9 = 2n^2 +8
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n^2 +9n + 1 = 0
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Solve using the Quadratic formula
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Cheers,
Stan H.
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Answer by MathLover1(20849) About Me  (Show Source):