Question 696896: find two consecative odd number such that one fifth of the smaller exceeds one ninth of the greater by 2 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find two consecutive odd numbers such that one fifth of the smaller exceeds one ninth of the greater by 2
-----
1st: 2x-1
2nd: 2x+1
-----
Equation:
(1/5)(2x-1) = (1/9)(2x+1) + 2
--------
Multiply thru by 45 to get:
9(2x-1) = 5(2x+1) + 90
-----
18x - 9 = 10x + 95
----
8x = 104
---
x = 13
----
1st: 2x-1 = 25
2nd: 2x+1 = 27
====================
Cheers,
Stan H.
============
(