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Question 696881: A number consists of two digits. The sum of the digit is 10. On reversing the digits of the number, the number decreases by 36. What is the product of the two digits ?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A number consists of two digits.
let a = the tens digit
let b = the units
then
10a+b = the "number"
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The sum of the digit is 10.
a + b = 10
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On reversing the digits of the number, the number decreases by 36.
10b + a = 10a + b - 36
Combine like terms
10b - b = 10a - a - 36
9b = 9a - 36
simplify, divide by 9
b = a - 4
-a + b = -4
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use elimination on the two equation
a + b = 10
-a + b = -4
------------------addition eliminates a, find b
2b = 6
b = 3
You should be able to find a, and check that it satisfies the the statement
"On reversing the digits of the number, the number decreases by 36. "
then answer the question
" What is the product of the two digits ?"
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