SOLUTION: Find the slope of the line passing through the points (1980, 18000) and (2000, 42000).

Algebra ->  Linear-equations -> SOLUTION: Find the slope of the line passing through the points (1980, 18000) and (2000, 42000).       Log On


   

Question 696670: Find the slope of the line passing through the points (1980, 18000) and (2000, 42000).
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Note: is the first point . So this means that x%5B1%5D=1980 and y%5B1%5D=18000.
Also, is the second point . So this means that x%5B2%5D=2000 and y%5B2%5D=42000.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%2842000-18000%29%2F%282000-1980%29 Plug in y%5B2%5D=42000, y%5B1%5D=18000, x%5B2%5D=2000, and x%5B1%5D=1980


m=%2824000%29%2F%282000-1980%29 Subtract 18000 from 42000 to get 24000


m=%2824000%29%2F%2820%29 Subtract 1980 from 2000 to get 20


m=1200 Reduce


So the slope of the line that goes through the points and is m=1200