SOLUTION: Solve algebraically for x: so there's a radical sign over 3x+1 and then +1 which is not included in the radical sign=x 3x+1+1=x *Radical sign is over 3x+1 Please help and thank

Algebra ->  Test -> SOLUTION: Solve algebraically for x: so there's a radical sign over 3x+1 and then +1 which is not included in the radical sign=x 3x+1+1=x *Radical sign is over 3x+1 Please help and thank      Log On


   

Question 696661: Solve algebraically for x: so there's a radical sign over 3x+1 and then +1 which is not included in the radical sign=x
3x+1+1=x
*Radical sign is over 3x+1
Please help and thank you very much. I really appreciate it!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%283x%2B1%29%2B1=x

sqrt%283x%2B1%29=x-1

3x%2B1=%28x-1%29%5E2

0=%28x-1%29%5E2-3x-1

%28x-1%29%5E2-3x-1=0

x%5E2-2x%2B1-3x-1=0

x%5E2-5x=0

x%28x-5%29=0

x=0 or x-5=0

x=0 or x=5

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So the two *possible* answers are x=0 or x=5

However, only one of these solutions actually work (ie are actually solutions).

You have to check to see if they work (which is something I leave for you to do)