SOLUTION: Solve for x: 3^2x=27^x+1 2. Solve for x: 25^x-1=125^x 3.Solve for x: 16^x-2=(1/8)^x Please help me.We didn't even learn any of this is class and I don't know to how solve it o

Algebra ->  Test -> SOLUTION: Solve for x: 3^2x=27^x+1 2. Solve for x: 25^x-1=125^x 3.Solve for x: 16^x-2=(1/8)^x Please help me.We didn't even learn any of this is class and I don't know to how solve it o      Log On


   

Question 696650: Solve for x: 3^2x=27^x+1
2. Solve for x: 25^x-1=125^x
3.Solve for x: 16^x-2=(1/8)^x
Please help me.We didn't even learn any of this is class and I don't know to how solve it or start it. Please help. Step by step procedure will be helpful. Thanks in advance!
Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Solve for x: 3^2x=27^x+1
2. Solve for x: 25^x-1=125^x
3.Solve for x: 16^x-2=(1/8)^x
Please help me.We didn't even learn any of this is class and I don't know to how solve it or start it. Please help. Step by step procedure will be helpful. Thanks in advance!

3%5E%282x%29+=+27%5E%28x+%2B+1%29+

3%5E%282x%29+=+%283%5E3%29%5E%28x+%2B+1%29+

3%5E%282x%29+=+3%5E%283x+%2B+3%29+

2x = 3x + 3 ---- When bases are equal, so are their exponents
2x – 3x = 3
- x = 3

x+=+3%2F-+1, or highlight_green%28-+3%29

Use the same concept to solve no. 2

16%5E%28x+-+2%29+=+%281%2F8%29%5Ex+

%282%5E4%29%5E%28x+-+2%29+=+%282%5E-+3%29%5Ex+

%282%5E4%29%5E%28x+-+2%29+=+2%5E%28-+3x%29

4(x – 2) = - 3x ---- When bases are equal, so are thier exponents
4x – 8 = - 3x
4x + 3x = 8
7x = 8

highlight_green%28x+=+8%2F7%29

You can do the check!!

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