Question 696632: A survey was conducted to measure the height of men. In the survey, respondents were grouped by age. In the 20-29 group the groups were normally distributed, with a mean of 68.4 inches and a standard deviation of 4 inches. A study participant is randomly selected. Complete parts a through c
a. Find the probability that his height is less than 66 inches
b. FInd the probability that the height is between 66 and 71 inches
c. Find the probability that the height is more than 71 inches
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A survey was conducted to measure the height of men. In the survey, respondents were grouped by age. In the 20-29 group the groups were normally distributed, with a mean of 68.4 inches and a standard deviation of 4 inches. A study participant is randomly selected. Complete parts a through c
a. Find the probability that his height is less than 66 inches
z(66) = (66-68.4)/4 = -0.6
P(x < 66) = P(z < -0.6) = normalcdf(-100,-0.6) = 0.2743
----------------------------------------------------------------
b. FInd the probability that the height is between 66 and 71 inches
z(71) = (71-68.4)/4 = 0.65
P(66< x <71) = P(-0.6< z <0.65) = normalcdf(-0.6,0.65) = 0.4675
------------------------------------
c. Find the probability that the height is more than 71 inches
P(x > 71) = P(z > 0.65) = normalcdf(0.65,100) = 0.2578
==========================
Cheers,
Stan H.
|
|
|
