Question 69638: solve: 
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 2x(x-1)< -3(2-2x)
2x^2-2x < -6+6x
2x^2-8x+6<0
x^2-4x+3<0
(x-3)(x-1)<0
Mark 1 and 3 on a number line ; this determines 3 intervals.
Check a test point in each interval to see where the solution set lies:
Check x=0 in interval (-inf,1);(0-3)(0-1)<0; no, so no solution in (-inf,1)
Check x=2 in interval (1,3);(2-3)(2-1)<0; yes, that interval part of solution
Check x=10 in interval (3,inf); (10-3)(10-1)<0: no, so no solution in (3,inf)
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Conclusion: The solution set is the interval (1,3)
Cheers,
Stan H.
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