SOLUTION: x^4-4x^2+3=0

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Question 695982: x^4-4x^2+3=0
Answer by mouk(232) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E4-4x%5E2%2B3=0+
+%28x%5E2-3%29%28x%5E2-1%29+=0+

so either +x%5E2-3+=0+ giving:
+x%5E2=3+
+x+=+%22%22%2B-+sqrt%283%29+

or +x%5E2-1+=0+ giving:
+x%5E2=1+
+x+=+%22%22%2B-+1+

Hence the solutions are:
+x+=+%22%22%2B-+1+ and +x+=+%22%22%2B-+sqrt%283%29+