SOLUTION: Find the foci of the ellipse with the equation: ((x^2)/36))+((y^2)/(64))=1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the foci of the ellipse with the equation: ((x^2)/36))+((y^2)/(64))=1      Log On


   

Question 695930: Find the foci of the ellipse with the equation: ((x^2)/36))+((y^2)/(64))=1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the foci of the ellipse with the equation: ((x^2)/36))+((y^2)/(64))=1
This is an ellipse with vertical major axis: (denominator of y-term>denominator of x-term)
Its standard form of equation: %28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1, a>b, (h,k)=(x,y) coordinates of center.
..
For given equation:
center: (0,0)
a^2=64
b^2=36
c^2=a^2-b^2=64-36=28
c=√28≈5.3
foci: (0,0±c)=(0,0±√28)=(0,0±5.3)=(0,-5.3) and (0,5.3)