SOLUTION: The length of a rectangle is 5 feet more than the width. The perimeter is 38 feet. Find the length and width of the rectangle.

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 5 feet more than the width. The perimeter is 38 feet. Find the length and width of the rectangle.      Log On


   

Question 695882: The length of a rectangle is 5 feet more than the width. The perimeter is 38 feet. Find the length and width of the rectangle.
Answer by mouk(232) About Me  (Show Source):
You can put this solution on YOUR website!
Let the width of the rectangle be +w+


"The length of a rectangle is 5 feet more than the width":
so the dimensions of the rectangle are +w+ and +w%2B5+


"The perimeter is 38 feet":
+2w+%2B+2%28w%2B5%29+=+38+


"Find the length and width of the rectangle":
+2w+%2B+2w+%2B+10+=+38+
+4w+=+28+
+w+=+7+
So the width is 7 and the length is 11