SOLUTION: Please help me! 6x + 45 (less than or equal to) (-4x) - 105 Can I just take 4x from 6x which would be 2x + 45 (less than or equal to) -105 and then subtract 45 from both si

Algebra ->  Inequalities -> SOLUTION: Please help me! 6x + 45 (less than or equal to) (-4x) - 105 Can I just take 4x from 6x which would be 2x + 45 (less than or equal to) -105 and then subtract 45 from both si      Log On


   

Question 695839: Please help me!
6x + 45 (less than or equal to) (-4x) - 105
Can I just take 4x from 6x which would be
2x + 45 (less than or equal to) -105
and then subtract 45 from both sides,
2x (less than or equal to) -150 then divide by 2,
x = -75
Did I do this right? Thank you!
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
When the equation contains an inequality (<, >, <=, >=) the answer won't be one value. The answer won't be x= something. The answer is an inequality: x>= or <= something.


Solve an inequality (as long as there's no x values in the denominators of fractions) the same way you'd solve an equation, but with one exception. If you multiply or divide both sides by a negative number then flip the sign (< becomes > etc.).
6x+45<=-4x -105 ---> Add 4x to both sides and subtract 45 from both sides: 10x<=-150 ---> divide both sides by 10: x<=-15.


When in doubt about your answer plug it back into the equation to see if it's true.


Your answer x=-75 will work, but it's not the only answer.

Hope the solution helped. Sometimes you need more than a solution. Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)