SOLUTION: how would you solve:
log(x+1)+(x-7)=log(10x+10)
this is what i did so far:
a. log(x+1)(x-7)=log(10x+10)
b.log (x+1)(x+7)/(10x+10)---> is this correct...now am stuck i don't kn
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-> SOLUTION: how would you solve:
log(x+1)+(x-7)=log(10x+10)
this is what i did so far:
a. log(x+1)(x-7)=log(10x+10)
b.log (x+1)(x+7)/(10x+10)---> is this correct...now am stuck i don't kn
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Question 695513: how would you solve:
log(x+1)+(x-7)=log(10x+10)
this is what i did so far:
a. log(x+1)(x-7)=log(10x+10)
b.log (x+1)(x+7)/(10x+10)---> is this correct...now am stuck i don't know the next step or if i even did it correctly
Thank you in advance! Found 2 solutions by mouk, MathTherapy:Answer by mouk(232) (Show Source):
You can put this solution on YOUR website! how would you solve:
log(x+1)+(x-7)=log(10x+10)
this is what i did so far:
a. log(x+1)(x-7)=log(10x+10)
b.log (x+1)(x+7)/(10x+10)---> is this correct...now am stuck i don't know the next step or if i even did it correctly
Thank you in advance!
Is this , or is it: ?
If it's the latter, then we have:
Since this actually means: , then:
(x + 1)(x - 17) = 0
x = - 1 (ignore as CANNOT BE = 0, NOR CAN BE < 0)
Therefore, only solution is:
You can do the check!!
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
