SOLUTION: Solve 1-log(3x+1)=log(x-2) log base =10

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Question 695491: Solve 1-log(3x+1)=log(x-2)
log base =10
Answer by lwsshak3(11628) About Me  (Show Source):
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Solve 1-log(3x+1)=log(x-2)
log base =10
1-log(3x+1)=log(x-2)
1=log(x-2)+log(3x+1)
log(10)=log[(x-2)(3x+1)]
(x-2)(3x+1)=10
3x^2-5x-2=10
3x^2-5x-12=0
(x-3)(3x+4)=0
x=3
or
x=-4/3 (reject, (x-2)>0