SOLUTION: {{{x^2+14xy+45y^2}}}

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Question 695305: x%5E2%2B14xy%2B45y%5E2
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression x%5E2%2B14xy%2B45y%5E2, we can see that the first coefficient is 1, the second coefficient is 14, and the last coefficient is 45.


Now multiply the first coefficient 1 by the last coefficient 45 to get %281%29%2845%29=45.


Now the question is: what two whole numbers multiply to 45 (the previous product) and add to the second coefficient 14?


To find these two numbers, we need to list all of the factors of 45 (the previous product).


Factors of 45:
1,3,5,9,15,45
-1,-3,-5,-9,-15,-45


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 45.
1*45 = 45
3*15 = 45
5*9 = 45
(-1)*(-45) = 45
(-3)*(-15) = 45
(-5)*(-9) = 45

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 14:


First NumberSecond NumberSum
1451+45=46
3153+15=18
595+9=14
-1-45-1+(-45)=-46
-3-15-3+(-15)=-18
-5-9-5+(-9)=-14



From the table, we can see that the two numbers 5 and 9 add to 14 (the middle coefficient).


So the two numbers 5 and 9 both multiply to 45 and add to 14


Now replace the middle term 14xy with 5xy%2B9xy. Remember, 5 and 9 add to 14. So this shows us that 5xy%2B9xy=14xy.


x%5E2%2Bhighlight%285xy%2B9xy%29%2B45y%5E2 Replace the second term 14xy with 5xy%2B9xy.


%28x%5E2%2B5xy%29%2B%289xy%2B45y%5E2%29 Group the terms into two pairs.


x%28x%2B5y%29%2B%289xy%2B45y%5E2%29 Factor out the GCF x from the first group.


x%28x%2B5y%29%2B9y%28x%2B5y%29 Factor out 9y from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B9y%29%28x%2B5y%29 Combine like terms. Or factor out the common term x%2B5y


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Answer:


So x%5E2%2B14xy%2B45y%5E2 factors to %28x%2B9y%29%28x%2B5y%29.


In other words, x%5E2%2B14xy%2B45y%5E2=%28x%2B9y%29%28x%2B5y%29.


Note: you can check the answer by expanding %28x%2B9y%29%28x%2B5y%29 to get x%5E2%2B14xy%2B45y%5E2 or by graphing the original expression and the answer (the two graphs should be identical).