Question 69518: x^2-8x+16=
x^2-17x+16=
x^2-8x+15
Answer by funmath(2933)   (Show Source):
You can put this solution on YOUR website! x^2-8x+16=
(x___)(x___)
To factor, fill the blanks with two integers that multiply to give you +16, but add to give you -8.
-4*-4=+16 and -4+(-4)=-8
(x-4)(x-4)
(x-4)^2
If this was supposed to be solved,
x-4=0
x-4+4=0+4
x=4
:
x^2-17x+16=
(x___)(x___)
Two integers that multiply to give you +16, but add to give you -17:
-1*-16=+16 and -1+(-16)=-17
(x-1)(x-16)
If this was supposed to be solved:
x-1=0 or x-16=0
x-1+1=0+1 or x-16+16=0+16
x=1 or x=16
:
x^2-8x+15
(x___)(x___)
Two numbers that multiply to give you +15, but add to give you -8:
-3*-5=+15 and -3+(-5)=-8
(x-3)(x-5)
If you were supposed to solve for x:
x-3=0 or x-5=0
x-3+3=0+3 or x-5+5=0+5
x=3 or x=5
Happy Calculating!!!!
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