SOLUTION: find 2 consecutive integers such that the larger is nine more than twice the smaller

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Question 694986: find 2 consecutive integers such that the larger is nine more than twice the smaller
Found 2 solutions by lynnlo, MathTherapy:
Answer by lynnlo(4176) About Me  (Show Source):
Answer by MathTherapy(10555) About Me  (Show Source):
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find 2 consecutive integers such that the larger is nine more than twice the smaller

Let the smaller integer be S
Then larger = S + 1

Therefore, S + 1 = 2S + 9

S - 2S = 9 - 1

- S = 8

S, or smaller number = 8%2F-1, or highlight_green%28-+8%29

Larger integer = - 8 + 1, or highlight_green%28-+7%29

You can do the check!!

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