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| Question 69492:  question......write an equation in point slope form and slope intercept form of the line passing through (-12,1) and perpendicular to the line whose equation is 6x-y-4=0
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! question......write an equation in point slope form and slope intercept form of the line passing through (-12,1) and perpendicular to the line whose equation is 6x-y-4=0 -----------------------------
 The given equation has a slope:
 y=6x-4, so the slope is 6
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 The perpendicular line must have slope of -1/6.
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 You want the equation of the line with slope=-1/6 passing though (-12,1)
 Use the point-slope form to get:
 y-1 = (-1/6)(x+12)
 y=(-1/6)x-1
 That is the equation you want.
 Cheers,
 Stan H.
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