SOLUTION: I need help with unit cancelling. If you planned to bike to a park that was 4.5 miles away, how fast do you need to pedal (in miles/hr) to get there in 75 minutes?

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Question 694804: I need help with unit cancelling. If you planned to bike to a park that was 4.5 miles away, how fast do you need to pedal (in miles/hr) to get there in 75 minutes?
Found 3 solutions by Ave, stanbon, MathTherapy:
Answer by Ave(106) About Me  (Show Source):
You can put this solution on YOUR website!
First convert minutes into hrs 75min=1.25hr
use the formula distance=rate*time
4.5=r*1.25 divide both sides by 1.25
3.6=r
so 3.6 miles per hour

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If you planned to bike to a park that was 4.5 miles away, how fast do you need to pedal (in miles/hr) to get there in 75 minutes?
----
Note: 75 min = (75/60) = 1 1/4 hrs = (5/4)hr
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Equation:
rate = distance/time = 4.5 miles / (5/4)hr
= (4*4.5)/5)mph
= 18/5 mph
= 3.6 mph
============
Cheers,
Stan H.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
I need help with unit cancelling. If you planned to bike to a park that was 4.5 miles away, how fast do you need to pedal (in miles/hr) to get there in 75 minutes?

%284.5miles%29%2F75minutes+=+%2860minutes%29%2F1hour

%284.5miles%29%2F75cross%28minutes%29+=+%2860cross%28minutes%29%29%2F1hour ---- Canceling minutes

%284.5miles%29%2F5cross%2875%29+=+%284cross%2860%29%29%2F1hour ---- Canceling numerator and denominator

%28.9cross%284.5%29miles%29%2Fcross%285%29+=+4%2F1hour ---- Canceling numerator and denominator

3.6miles%2F1hour ----- highlight_green%283.6miles_per_hour%29