SOLUTION: a bus travel at 36 km per hour and arrive its destination half an hour late if the bus travel at 42 km per hour and it arrives at its destination half an hour earlier find the dist
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Question 694747: a bus travel at 36 km per hour and arrive its destination half an hour late if the bus travel at 42 km per hour and it arrives at its destination half an hour earlier find the distance Found 2 solutions by stanbon, sachi:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a bus travel at 36 km per hour and arrive its destination half an hour late if the bus travel at 42 km per hour and it arrives at its destination half an hour earlier find the distance
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Slower Bus DATA:
rate = 36 km/hr ; distance = x km ; time = d/r = x/36 hrs
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Faster Bus DATA:
rate = 42 km/hr ; distance = x km ; time = d/r = x/42 hrs
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Equation:
slow time - fast time = (1/2) hr
x/36 - x/42 = 1/2
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(42x-36x)/(36*42) = 1/2
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6x = 18*42
x = 18*7
x = 126 km
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Cheers,
Stan H.
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You can put this solution on YOUR website! let the distance is s km
the time taken at 36 km/hr speed =s/36 hr
the time taken at 42 km/hr speed =s/42 hr
the difference between two times= s/36-s/42=1 (1/2hr late+1/2 hr earlier=1 hr)
or s(42-36)=42*36
or s=42*36/6=252 km
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