SOLUTION: The sum of the digits of a two-digit number is 10. If the digits are reversed, the new number is 36 greater than the original number. Find the original number.
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Question 694691: The sum of the digits of a two-digit number is 10. If the digits are reversed, the new number is 36 greater than the original number. Find the original number. Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! The sum of the digits of a two-digit number is 10.
let the ones digit is x then tens digit is 10-x
then the no is 10(10-x)+x........original no
If the digits are reversed,
the no is 10x+(10-x)...........new no
the new number is 36 greater than the original number.
so 10x+(10-x)=36+10(10-x)+x
or 9x+10=136-9x
or 18x=136-10=126
or x=7 is the ones digit
so the tens digit ig 10-7=3
so the original number is 37
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