SOLUTION: The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 63 greater than the original number. Find the original number.
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Question 694688: The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 63 greater than the original number. Find the original number. Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! The sum of the digits of a two-digit number is 9.
let the ones digit is x then tens digit is 9-x
then the no is 10(9-x)+x........original no
If the digits are reversed,
the no is 10x+(9-x)...........new no
the new number is 63 greater than the original number.
so 10x+(9-x)=63+10(9-x)+x
or 9x+9=153-9x
or 18x=153-9=144
or x=8 is the ones digit
so the tens digit ig 10-8=1
so the original number is 18
