SOLUTION: What are the vertices of the hyperbola given by [(y-1)^2/4]-[(x-2)^2/16]=1?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What are the vertices of the hyperbola given by [(y-1)^2/4]-[(x-2)^2/16]=1?       Log On


   

Question 694602: What are the vertices of the hyperbola given by [(y-1)^2/4]-[(x-2)^2/16]=1?
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
%28y-1%29%5E2%2F4%22%22-%22%22%28x-2%29%5E2%2F16 = 1

It's in the form

%28y-k%29%5E2%2Fa%5E2%22%22-%22%22%28x-h%29%5E2%2Fb%5E2 = 1

The center is (h,k) = (2,1)

Because the term in y comes first, it's a hyperbola like this .

Therefore the vertices are "a" units above and below the center.

So they are (2,1±2), that is, (2,-1) and (2,3) 

Edwin