SOLUTION: what is the value for y when 5y^2-12y+35=0?

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Question 694596: what is the value for y when 5y^2-12y+35=0?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

y+=+%28-%28-12%29%2B-sqrt%28%28-12%29%5E2-4%285%29%2835%29%29%29%2F%282%285%29%29 Plug in a+=+5, b+=+-12, c+=+35

y+=+%2812%2B-sqrt%28144-%28700%29%29%29%2F%2810%29

y+=+%2812%2B-sqrt%28-556%29%29%2F10

y+=+%2812%2Bsqrt%28-556%29%29%2F10 or y+=+%2812-sqrt%28-556%29%29%2F10

y+=+%2812%2B2i%2Asqrt%28139%29%29%2F10 or y+=+%2812-2i%2Asqrt%28139%29%29%2F10

y+=+%286%2Bi%2Asqrt%28139%29%29%2F5 or y+=+%286-i%2Asqrt%28139%29%29%2F5