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Question 694349: How do you write an equation of the line that passes through the point (6, 2) and is parallel to the line y = 1/2 x – 1
Answer by Ave(106)   (Show Source):
You can put this solution on YOUR website! use point slope form:
y-y1=slope(x-x1) slope of parallel lines are equal so the slope is 1/2. x1 and y1 are the point coordinates (6,2)
y-2=1/2(x-6) times both sides by 2 to get rid of fraction
2y-4=x-6 add 4 to both sides
2y=x-2 divide by 2
y=1/2x-1
since it's the same equation there are no lines parallel, because the original line passes through (6,2)
If you wanted a perpendicular line going through (6,2) you would do the same thing except use -2 for the slope.
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