SOLUTION: find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2

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Question 69429: find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2
Found 2 solutions by tutorcecilia, funmath:
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
Use the point-slope equation:
(y-y1)=m(x-x1)[plug-in the values and simplify]
(y-(-3))=(-1/2)((x-1)
y+3=-1/2x+1/2 [Solve for y]
y=-1/2x+1/2-3
y=-1/2x-5/2

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2
When give a point, (x1,y1), and a slope, m, and asked for an equation of the line, use the point-slope formula, highlight%28y-y%5B1%5D=m%28x-x%5B1%5D%29%29.
(x1,y1)=(1,-3) and m=-1/2
y-%28-3%29=%28-1%2F2%29%28x-1%29
The standard form of a line is highlight%28Ax%2BBy=C%29, where A, B, and C are integers. Some books require that A be positive.
y%2B3=%28-1%2F2%29%28x-1%29
2%28y%2B3%29=2%28-1%2F2%29%28x-1%29
2y%2B6=-%28x-1%29
2y%2B6=-x%2B1
x%2B2y%2B6=x-x%2B1
x%2B2y%2B6=1
x%2B2y%2B6-6=1-6
highlight%28x%2B2y=-5%29
Happy Calculating!!!