SOLUTION: Use the information provided to write the standard form equation of each hyperbola. Vertices: (-2, 8), (-2,-2) Endpoints of Conjugate Axis:(8,3) (-12,3)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Use the information provided to write the standard form equation of each hyperbola. Vertices: (-2, 8), (-2,-2) Endpoints of Conjugate Axis:(8,3) (-12,3)      Log On


   



Question 694202: Use the information provided to write the standard form equation of each hyperbola. Vertices: (-2, 8), (-2,-2) Endpoints of Conjugate Axis:(8,3) (-12,3)
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Use the information provided to write the standard form equation of each hyperbola. Vertices: (-2, 8), (-2,-2) Endpoints of Conjugate Axis:(8,3) (-12,3)
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This is a hyperbola with vertical transverse axis (y-coordinates of vertices change but x-coordinates do not)
Its standard form of equation: %28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (-2,3) (midpoints of changing x and y-coordinates)
length of vertical transverse axis=10(-2 to 8)=2a
a=5
a^2=25
length of conjugate axis=20 (-12 to 8)=2b
b=10
b^2=100
Equation of given hyperbola:%28y-3%29%5E2%2F25-%28x%2B2%29%5E2%2F100=1