SOLUTION: Identify the center and foci of the ellipse. (x-2)^2/16 + (y-7)^2/169 =1

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Question 694199: Identify the center and foci of the ellipse. (x-2)^2/16 + (y-7)^2/169 =1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Identify the center and foci of the ellipse. %28x-2%29%5E2%2F16+%2B+%28y-7%29%5E2%2F169+=1
This is an equation of an ellipse with vertical major axis.(y-denominator > x-denominator
Its standard form: %28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1, a>b, (h,k)=(x,y) coordinates of center
For given equation:
center: (2,7)
a^2=169
b^2=16
c^2=a^2-b^2=169/16=153
c=√153≈12.4
foci: (2,7±c)≈(2,7±12.4)≈(2,-5.4 and (2,19.4)