Question 694194: what is the vertex, axis of symmetry, and direction of opening for y=x^2-18x+79?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! what is the vertex, axis of symmetry, and direction of opening for
y=x^2-18x+79?
complete the square
y=(x^2-18x+81)+79-81
y=(x-9)^2-3
This is an equation of a parabola that opens upwards. (lead coefficient positive)
Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex.
For given equation: y=(x-9)^2-3
vertex:(9,-3)
Axis of symmetry: x=9
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