SOLUTION: I don't understand how to preform the operations with complex numbers like with;
(6-5i)(4-9i) and also like; please help, I need to get my grade back to a B by tmoorrow...
2+3i/
Question 694095: I don't understand how to preform the operations with complex numbers like with;
(6-5i)(4-9i) and also like; please help, I need to get my grade back to a B by tmoorrow...
2+3i/
4-5i Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (6-5i)(4-9i)
Use FOIL:
F: 6*4 = 24
O:6*-91 = -54i
I:-5i*4 = -20i
L:-5i*-9i = -45
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Combine to get:
-21 -74i
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(2+3i)/(4-5i)
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Multiply numerator and denominator by (4+5i) to get:
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= [(2+3i)(4+5i)]/[(4-5i)(4+5i)]
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= [8-15 + 21i+10i] / [16+25]
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= [-7+31i]/41
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Cheers,
Stan H.
You can put this solution on YOUR website! you have to know that
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To multiply , you need
to know the more basic operation
You're doing the same thing with operations on
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Multiply top and bottom by
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It's easy to make a mistake on these, but
I hope you get the idea
(