SOLUTION: how do you solve these equations 1) e^-x=5 2) 11^5x=33 3) 4e^2x=17
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Question 694003
:
how do you solve these equations
1) e^-x=5
2) 11^5x=33
3) 4e^2x=17
Answer by
lwsshak3(11628)
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how do you solve these equations
1) e^-x=5
-xlne=ln5
x=-ln5
..
2) 11^5x=33
5xlog11=log33
5x=log33/log11
x=(log33/log11)/5
x≈0.2916
..
3) 4e^2x=17
ln4+2xlne=ln17
2x=ln17-ln4
x=(ln17-ln4)/2
x≈.7235