Question 693852: urgent help
its a complex fraction
x^2-5x+6/x+6/x^2-4x+4/x^2-9
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! x^2-5x+6/x+6/x^2-4x+4/x^2-9
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Factor:
[(x-3)(x-2)/(x+6)] divided by [(x-2)^2/(x+3)(x-3)]
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Invert the denominator and multipl:
[(x-3)(x-2)/(x+6)] times [[(x+3)(x-3)]/(x-2)^2]
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Cancel any factors common to a numerator and a denominator,
such as (x-3), (x-2), to get:
= [(x-3)/(x+6)] times [[(x+3)(x-3)]/(x-2)]
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= [(x-3)^2(x+3)]/[(x+6)(x-2)]
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Cheers,
Stan H.
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