SOLUTION: logx=2-log(x+48)
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Question 693605
:
logx=2-log(x+48)
Answer by
stanbon(75887)
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logx=2-log(x+48)
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log(x) + log(x+48) = 2
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log[x(x+48)] = 2
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x^2+48x = 100
x^2 + 48x - 100 = 0
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Factor:
x^2+50x-2x-100 = 0
x(x+50)-2(x+50) = 0
(x+50)(x-2) = 0
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Positive solution:
x = 2
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cheers,
Stan H.