SOLUTION: how do i do Given the function, (1/3X) + 3/4 = Y, what is Y when X = 1?

Algebra ->  Functions -> SOLUTION: how do i do Given the function, (1/3X) + 3/4 = Y, what is Y when X = 1?      Log On


   

Question 693436: how do i do Given the function, (1/3X) + 3/4 = Y, what is Y when X = 1?
Found 2 solutions by RedemptiveMath, MathLover1:
Answer by RedemptiveMath(80) About Me  (Show Source):
You can put this solution on YOUR website!
All we need to do is put 1 wherever we find x in the equation. Once we "plug" 1 in for x, we solve using order of operations. So,

(1/3X) + 3/4 = Y (writing your equation)
(1/3)(1) + 3/4 = Y (I'm assuming that 3 in 1/3 and x are being multiplied?)
1/3 + 3/4 = Y (multiplication before addition)
4/12 + 9/12 = Y (find common denominators before adding fractions)
13/12 = Y (add)
1 1/12 = Y (rewrite improper fraction as mixed number).

It depends on your teacher whether you keep the fraction improper or write it as a mixed number. You can now say that when x is 1, y is 1 and 1/12 or 13/12.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
if you have this:
%281%2F3%29x+%2B+3%2F4+=+y, what is y when x+=+1
plug in x+=+1
%281%2F3%29%2A1+%2B+3%2F4+=+y

1%2F3+%2B+3%2F4+=+y

4%2A1%2F%283%2A4%29+%2B+3%2A3%2F%284%2A3%29+=+y

4%2F12+%2B+9%2F12+=+y

13%2F12+=+y

1.0833333333333333333333333333333=+y
y=1.08

+graph%28+600%2C600%2C+-5%2C+5%2C+-5%2C+5%2C+%281%2F3%29x+%2B+3%2F4%29+

but, if you have this:
%281%2F3x%29+%2B+3%2F4+=+y, what is y when x+=+1
plug in x+=+1
%281%2F3%2A1%29+%2B+3%2F4+=+y

1%2F3+%2B+3%2F4+=+y

4%2A1%2F%283%2A4%29+%2B+3%2A3%2F%284%2A3%29+=+y

4%2F12+%2B+9%2F12+=+y

13%2F12+=+y

1.0833333333333333333333333333333=+y

y=1.08

+graph%28+600%2C600%2C+-5%2C+5%2C+-5%2C5%2C+1%2F%283x%29+%2B3%2F4%29+
as you can see, in both cases the solution happens to be same