SOLUTION: Mr. Munch is twice as old as his daughter. In two years, he will be four times as old as his daughter was fifteen years ago. How old are they now?

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Question 693151: Mr. Munch is twice as old as his daughter. In two years, he will be four times as old as his daughter was fifteen years ago. How old are they now?

Found 2 solutions by stanbon, DrBeeee:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Mr. Munch is twice as old as his daughter. In two years, he will be four times as old as his daughter was fifteen years ago. How old are they now?
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Equations:
m = 2d
m+2 = 4(d-15))
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Substitute for "m" and solve for "d"
2d+2 = 4d-60
2d = 62
daughter = 31 yrs
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Solve for "m":
m = 2d
Mr. Munch = 2*31 = 62 yrs
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Cheers,
Stan H.

Answer by DrBeeee(684) (Show Source):
You can put this solution on YOUR website!
Let M = Mr. Munch's present age
Let D = his daughter's present age.
The problem statement gives use two equations
(1) M = 2*D and
(2) M + 2 = 4*(D - 15)
To solve, substitute (1) into (2) to get
(3) 2*D + 2 = 4*D - 60 or
(4) 2*D = 62 or
(5) D = 31, then using (1) we get
(6) M = 62
Check these answers with (2).
Is (62 + 2 = 4*(31 - 15))?
Is (64 = 4*16)?
Is (64 = 64)? Yes
Answer: Mr. Munch is 62 and his daughter is 31.