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Question 69312This question is from textbook An Incremental Development
: The number of moose varied inversely as the number of bears and directly as the number of bison. When there were 75 moose, there were 85 bears and 15 Bison. How many bears were there when there were 10 moose and 30 bison?
This question is from textbook An Incremental Development
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! umber of moose varied inversely as the number of bears and directly as the number of bison. When there were 75 moose, there were 85 bears and 15 Bison. How many bears were there when there were 10 moose and 30 bison?
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I see this one has reappeared. Last time I tried it I got (what I thought) was an
outrageous answer, but at the risk of looking ridiculous, here is a method:
:
Moose = (Bison/Bears) * k
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75 = 15k/85: find k
15k = 75 * 85
15k = 6375
k = 6375/15
k = 425
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"How many bears (b) were there when there were 10 moose and 30 bison?"
10 = (30k)/b
10 = (30*425)/b
10b = 12750
b = 12750/10
b = 1275 bears
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