SOLUTION: The solution for x-7<-12 is x<-5 . My text book recommends checking the solution by substituting -5 into the equation x-7=-12 to see if -5 is the correct boundary point, if -12=-12

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The solution for x-7<-12 is x<-5 . My text book recommends checking the solution by substituting -5 into the equation x-7=-12 to see if -5 is the correct boundary point, if -12=-12      Log On


   



Question 692859: The solution for x-7<-12 is x<-5 . My text book recommends checking the solution by substituting -5 into the equation x-7=-12 to see if -5 is the correct boundary point, if -12=-12 then -5 is the correct boundary point.
My question is this, why & where does the idea of plugging in -5 into x-7=-12 to see if it's the correct endpoint or boundary point come from? What does the equation have to do with the inequality???
Thanks
Ralph

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Since you get +x+%3C+-5+, my method is to
check by saying +x+=+-5.001+
+x+-+7+%3C+-12+
+-5.001+-+7+%3C+-12+
+-12.001+%3C+-12+
This is true
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What they say is " For what value of +x+ does
the inequality begin to fail ?"
They could have said it fails for
+x+%3C+-4.999+, but it also fails for
+x+%3C+-4.9999+ , and also for
+x+%3C+-4.99999+
This approaches +x+=+-5+
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Also, they could say the inequality passes for
+x+%3E+-5.001+, but also for
+x+%3E+-5.0001+ also for
+x+%3E+-5.00001+
It does not pass when
+x+=+-5+
Hope this helps