SOLUTION: Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval [0,pi).

Algebra ->  Trigonometry-basics -> SOLUTION: Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval [0,pi).      Log On


   

Question 69280: Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval [0,pi).
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find all solutions of the equation 2sin(2x)=sqr rt of 3 in the interval [0,pi).
------------
2sin(2x) = sqrt(3)
sin(2x) = [sqrt(3)]/2
2x=(pi/3 or (2/3)pi)
x=(pi/6 or pi/3)
Cheers,
Stan H.