SOLUTION: 1)the directions ask: convert to an exponential equation ln3^a=1.7 2) the directions ask: find a polynomial function of degree 3 with 1+2i,1-2i,-1 as zeros.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 1)the directions ask: convert to an exponential equation ln3^a=1.7 2) the directions ask: find a polynomial function of degree 3 with 1+2i,1-2i,-1 as zeros.       Log On


   



Question 692701: 1)the directions ask: convert to an exponential equation
ln3^a=1.7
2) the directions ask: find a polynomial function of degree 3 with 1+2i,1-2i,-1 as zeros.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1)the directions ask: convert to an exponential equation
ln3^a=1.7
base = e
exponent = ln = 1.7
result = 3^a
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Exponential Form:
e^1.7 = 3^a
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2) the directions ask: find a polynomial function of degree 3 with 1+2i,1-2i,-1 as zeros.
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f(x) = (x-(1+2i))(x-(1-2i)(x+1)
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= ((x-1)-2i)((x-1)+2i)(x+1)
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= ((x-1)^2+4))(x+1)
----
= (x^2-2x+8)(x+1)
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= x^3 + +x^2 -2x^2 -2x+8x+8
----
= x^3-x^2+6x+8
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Cheers,
Stan H.
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