SOLUTION: I need with a Linear Equations Word problem in Algebra 1. Here it is:
One pipe can be used to fill a tank in 48 min and another can be used to fill it in 1 hour and 12 min. How l
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-> SOLUTION: I need with a Linear Equations Word problem in Algebra 1. Here it is:
One pipe can be used to fill a tank in 48 min and another can be used to fill it in 1 hour and 12 min. How l
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Question 692384: I need with a Linear Equations Word problem in Algebra 1. Here it is:
One pipe can be used to fill a tank in 48 min and another can be used to fill it in 1 hour and 12 min. How long will it take to fill the tank if both pipes are used. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! One pipe can be used to fill a tank in 48 min and another can be used to fill it in 1 hour and 12 min.
How long will it take to fill the tank if both pipes are used.
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Convert 1 hr 12 min, to min: 60 + 12 = 72 min
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Let t = time (in min) to fill the tank using both pipes
;
Let the competed job = 1; (a full tank)
:
Each pipe will do a fraction of the job, the two fractions add up to 1
: + = 1
Multiply by the least common multiple to clear the denominators
144* + 144* = 144
cancel the denominators and you have
3t + 2t = 144
5t = 144
t = 144/5
t = 28.8 min working together
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Check this using a calc + =
.6 + .4 = 1; confirms our solution to 28.8
