Question 69219: find the LCD of
1 1
------- + ------
1 - x^2 x - 1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find the LCD of
1 1
------- + ------
1 - x^2 x - 1
============================
Multiply numerator and denominator of the 1st fraction
by negative one to get:
[-1/(x^2-1)] + [1/(x-1)]
Factor to get:
=[-1/(x-1)(x+1)] + [1/(x-1)]
The lcd is (x-1)(x+1)
Rewrite each fraction with the lcd as its denominator:
=[-1/lcd + (x+1)/lcd]
Combine the numerators to get:
=[-1+x+1]/lcd
=x/(x+1)(x-1)
Cheers,
Stan H.
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