SOLUTION: how do i find the asymptotes and intercepts of g(x)= 2x^2/x-4

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Question 692081: how do i find the asymptotes and intercepts of g(x)= 2x^2/x-4
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find the asymptotes and intercepts of g(x)= 2x^2/x-4
vertical asymptotes:
set denominator=0, then solve for x
x-4=0
x=4
..
since degree of numerator is one more than the degree of the denominator, a slant asymptote exists. 2x^2/x-4=2x+remainder.
slant asymptote: y=2x
..
horizontal asymptote:none
..
x-intercept:
set y=0
2x^2=0
x=0
..
y-intercept:
set x=0
y=2x^2/x-4
y=0/-4
y=0