SOLUTION: solve the following equation for θ of 0° and 360° 3sin^2θ + sinθ=0

Algebra ->  Trigonometry-basics -> SOLUTION: solve the following equation for θ of 0° and 360° 3sin^2θ + sinθ=0      Log On


   



Question 692002: solve the following equation for θ of 0° and 360°
3sin^2θ + sinθ=0

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve the following equation for θ of 0° and 360°
3sin^2θ + sinθ=0
sinθ(3sinθ+1)=0
sinθ=0
θ=0 and 180º
..
3sinθ+1=0
sinθ=-1/3
reference angle≈19.47º
θ≈199.47º and 340.53º (In quadrants III and IV where sin<0)