SOLUTION: Solve. If problem has no solution; write no solution. 1 = 3 over y+2 + 1 over y-2 Here is what I have: (y+2)(y-2) = 3(y-2)+ y + 2 y^2 + 2y - 2y - 4 = 3y - 6

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Solve. If problem has no solution; write no solution. 1 = 3 over y+2 + 1 over y-2 Here is what I have: (y+2)(y-2) = 3(y-2)+ y + 2 y^2 + 2y - 2y - 4 = 3y - 6       Log On


   

Question 69181This question is from textbook Algebra Structure and Method
: Solve. If problem has no solution; write no solution.
1 = 3 over y+2 + 1 over y-2

Here is what I have:

(y+2)(y-2) = 3(y-2)+ y + 2
y^2 + 2y - 2y - 4 = 3y - 6 + y + 2
y^2 - 4 = 4y - 4
and that is as far as I got, I am lost
 This question is from textbook Algebra Structure and Method

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You did fine as far as you went so let's continue from where you left off:
y%5E2-4+=+4y-4 Add 4 to both sides of the equation.
y%5E2+=+4y Subtract 4y from both sides.
y%5E2-4y+=+0 Factor a y on the left side.
y%28y-4%29+=+0 Apply the zero product principle.
y+=+0 and/or y-4+=+0
The solutions are:
y+=+0
y+=+4