SOLUTION: log(x-1)+log(x+1)=Log(x+2)^2
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Question 691758
:
log(x-1)+log(x+1)=Log(x+2)^2
Answer by
stanbon(75887)
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log(x-1)+log(x+1)=Log(x+2)^2
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log[(x-1)(x+1)] = log(x+2)^2
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x^2-1 = (x+2)^2
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x^2-1 = x^2 + 4x + 4
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4x = -5
x = -5/4
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Result: No solution as that solution is extraneous.
Cheers,
Stan H.