Question 691659: Can you help me find the center, foci, vertices, length of the major and minor axis of (x+2)^2/25+ (y-3)/49= 1?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the center, foci, vertices, length of the major and minor axis of
(x+2)^2/25+ (y-3)^2/49= 1?
This is an equation of an ellipse with vertical major axis.
Its standard form of equation: (x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k)=(x,y) coordinates of center
For given equation:
center: (-2,3)
a^2=49
a=√49=7
length of vertical major axis=2a=14
vertices: (-2,3±a), (-2,3±7)=(-2,-4) and (-2,10)
b^25
b=√25=5
length of minor axis=2b=10
c^2=a^2-b^2=49-25=24
c=√24≈4.9
foci:(-2,3±c), (-2,3±4.9)=(-2,-1.9) and (-2,7.9)
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