Question 691658: Can you help me find the vertex, focus, and the equation of the directrix of (x-4)^2=8(x+3)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! find the vertex, focus, and the equation of the directrix of find the vertex, focus, and the equation of the directrix of (y-4)^2=8(x+3)
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I think you meant to write given equation as (y-4)^2=8(x+3)
This is an equation of a parabola that opens rightwards:
Its standard form:((y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex, p=distance from the vertex to the focus and directrix on the axis of symmetry.
For given equation: (y-4)^2=8(x+3)
vertex: (-3,4)
axis of symmetry: y=4
4p=8
p=4
focus: (1,4)
directrix: x=-7
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